document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=233890>Question 233890</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Andrew can lay carpet in a house in ten hours. If Mary helps him, they can get the carpet down in six hours. What is the number of hours it takes Mary to do the job by herself. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #172537 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=172537\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">     Andrew can lay carpet in a house in ten hours. If Mary helps him, they can get the carpet down in six hours. What is the number of hours it takes Mary to do the job by herself.<BR>\n" );
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document.write( "Let x = number of hours Mary can do the job by herself<BR>\n" );
document.write( "then<BR>\n" );
document.write( "6(1/10 + 1/x) = 1<BR>\n" );
document.write( "6/10 + 6/x) = 1<BR>\n" );
document.write( "Multiplying both sides by 10x:<BR>\n" );
document.write( "6x + 60 = 10x<BR>\n" );
document.write( "60 = 4x<BR>\n" );
document.write( "15 hours = x\r<BR>\n" );
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