document.write( "Question 233867: find the consecutive odd itergers such that twice the larger is 17 more than the smaller \n" ); document.write( "
Algebra.Com's Answer #172532 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! LET X & X+2 BE THE 2 ODD INTEGERS. \n" ); document.write( "2(X+2)=X+17 \n" ); document.write( "2X+4=X+17 \n" ); document.write( "2X-X=17-4 \n" ); document.write( "X=13 ANS. \n" ); document.write( "13+2=15 ANS. \n" ); document.write( "PROOF: \n" ); document.write( "2*15=13+17 \n" ); document.write( "30=30\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |