document.write( "Question 233868: The length of a rectangle is 12 times longer than the width. The perimeter is 84. What is the width? 84=2(12w)+2w...84=24w+2w Am I doing right? \n" ); document.write( "
Algebra.Com's Answer #172530 by checkley77(12844)\"\" \"About 
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L=12W
\n" ); document.write( "P=84
\n" ); document.write( "P=2L+2W
\n" ); document.write( "84=2(12w)+2w
\n" ); document.write( "84=24w+2w
\n" ); document.write( "84=26W
\n" ); document.write( "84/26=W
\n" ); document.write( "3.231=W ANS. FOR THE WIDTH.
\n" ); document.write( "L=12*3.231=38.76 ANS. FOR THE LENGTH
\n" ); document.write( "PROOF:
\n" ); document.write( "84=2*38.77+2*3.23
\n" ); document.write( "84=77.54+6.46
\n" ); document.write( "84=84
\n" ); document.write( "
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