document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=233809>Question 233809</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a lot is in the shape of a right triangle. The hypotenuse is 3m longer than the longer leg. The longer leg is 6m longer than twice the length of the shorter leg. Find the perimeter. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #172526 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=172526\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> C=B+3 OR B=C-3<BR>\n" );
document.write( "B=2A+6 <BR>\n" );
document.write( "C-3=2A+6<BR>\n" );
document.write( "C=2A+9<BR>\n" );
document.write( "A^2+B^2=C^2<BR>\n" );
document.write( "A^2+(2A+6)^2=(2A+9)^2<BR>\n" );
document.write( "A^2+4A^2+24A+36=4A^2+36A+81 CANCEL OUT THE 4X^2 TERMS & COMBINE LIKE TERMS:<BR>\n" );
document.write( "A^2+24A-36A+36-81=0<BR>\n" );
document.write( "A^2-12A-45=0 FACTOR THE EUATION.<BR>\n" );
document.write( "(A-15)(A+3)=0<BR>\n" );
document.write( "A-15=0<BR>\n" );
document.write( "A=15 ANS. FOR THE SHORT LEG.<BR>\n" );
document.write( "B=2*15+6=30+6=36 ANS. FOR THE LONG LEG.<BR>\n" );
document.write( "C=36+3=39<BR>\n" );
document.write( "FOR THE HYPOTENUSE.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "15^2+36^2=39^2<BR>\n" );
document.write( "225+1296=1521<BR>\n" );
document.write( "1521=1521<BR>\n" );
document.write( "THEREFORE THE PERIMETER=15+36+39=90 m. \r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );