document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=233810>Question 233810</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of a triangle is 30 square inches. The base of the triangle measures 2 in more than twice the height of the triangle. Find the measures of the base and the height.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #172521 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=172521\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A=BH/2 TRIANGLE AREA FORMULA.<BR>\n" );
document.write( "B=2H+2 SUBSTITUTE (2H+2) FOR B IN THE AREA FORMULA & SOLVE FOR H.<BR>\n" );
document.write( "30=(2H+2)H/2<BR>\n" );
document.write( "30=(2H^2+2H)/2 CROSS MULTIPLY.<BR>\n" );
document.write( "2H^2+2H=60<BR>\n" );
document.write( "2H^2+2H-60=0 DIVIDE ALL TERMS BY 2.<BR>\n" );
document.write( "2(H^2+H-30)=0 <BR>\n" );
document.write( "2(H+6)(H-5)=0<BR>\n" );
document.write( "H-5=0<BR>\n" );
document.write( "H=5 ANS. FOR THE HEIGHT.<BR>\n" );
document.write( "B=2*5+2=10+2=12 ANS. FOR THE BASE.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "30=5*12/2<BR>\n" );
document.write( "30=60/2<BR>\n" );
document.write( "30=30 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );