document.write( "Question 233797: the perimeter of a rectangle is 128 inches. if the length of the rectangle is 8 less than twice the width, what are the dimensions of the rectangle? let l represent the length and w represent the width. \n" ); document.write( "
Algebra.Com's Answer #172501 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! the perimeter of a rectangle is 128 inches. if the length of the rectangle is 8 less than twice the width, what are the dimensions of the rectangle? let l represent the length and w represent the width. \n" ); document.write( "----------------------------------------- \n" ); document.write( "Perimeter = 2(l + w) \n" ); document.write( "128 = 2((2w-8)+w) \n" ); document.write( "64 = 3w-8 \n" ); document.write( "3w = 72 \n" ); document.write( "w = 24 in. (width) \n" ); document.write( "--- \n" ); document.write( "l = 2w-8 = 2*24-8 = 40 in. (length) \n" ); document.write( "=================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |