document.write( "Question 233797: the perimeter of a rectangle is 128 inches. if the length of the rectangle is 8 less than twice the width, what are the dimensions of the rectangle? let l represent the length and w represent the width. \n" ); document.write( "
Algebra.Com's Answer #172501 by stanbon(75887)\"\" \"About 
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the perimeter of a rectangle is 128 inches. if the length of the rectangle is 8 less than twice the width, what are the dimensions of the rectangle? let l represent the length and w represent the width.
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\n" ); document.write( "Perimeter = 2(l + w)
\n" ); document.write( "128 = 2((2w-8)+w)
\n" ); document.write( "64 = 3w-8
\n" ); document.write( "3w = 72
\n" ); document.write( "w = 24 in. (width)
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\n" ); document.write( "l = 2w-8 = 2*24-8 = 40 in. (length)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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