document.write( "Question 29297: solve each system using the substitution method. y-2x=-6,2y-x=5\r
\n" ); document.write( "\n" ); document.write( " next problem. 3a+2b=2,-2a+b=8
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Algebra.Com's Answer #17250 by sdmmadam@yahoo.com(530)\"\" \"About 
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y-2x=-6 ----(1)
\n" ); document.write( "2y-x=5 ----(2)
\n" ); document.write( "(1) implies y = 2x-6 ----(*)
\n" ); document.write( "(transposing -2x, change sign while changing side)
\n" ); document.write( "Putting (*) in (2),that is substituting for y
\n" ); document.write( "2(2x-6)-x=5
\n" ); document.write( "4x-12-x=5
\n" ); document.write( "(4x-x)= 5+12
\n" ); document.write( "3x=17
\n" ); document.write( "x=17/3
\n" ); document.write( "Putting x = 17/3 in (*)
\n" ); document.write( "y = 2x-6 = 2X(17/3)-6 = 34/3-6 = (34-18)/3 = 16/3
\n" ); document.write( "Answer: x = 17/3 and y = 16/3
\n" ); document.write( "Verification: Putting x = 17/3 and y = 16/3 in (2)
\n" ); document.write( "LHS = 2y-x = 32/3-17/3 = 15/3 =5 = RHS
\n" ); document.write( "Therefore our values are correct.\r
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\n" ); document.write( "\n" ); document.write( "2)
\n" ); document.write( "3a+2b=2 ----(1)
\n" ); document.write( "-2a+b=8 ----(2)
\n" ); document.write( "(2) implies
\n" ); document.write( "b = 8+2a ----(*)(transposing -2a, change sign while changing side)
\n" ); document.write( "Putting (*) in (1),that is substituting for b
\n" ); document.write( "3a+2(8+2a)= 2
\n" ); document.write( "3a+16+4a=2
\n" ); document.write( "(3a+4a) = 2-16
\n" ); document.write( "7a = -14
\n" ); document.write( "a = -14/7 = -2
\n" ); document.write( "a=-2 in (*) implies
\n" ); document.write( "b = 8+2a = 8+2X(-2) = 8-4 = 4
\n" ); document.write( "Answer: a = -2 and b = 4
\n" ); document.write( "Verification: Putting a = -2 and b = 4 in (1)
\n" ); document.write( "LHS = 3a+2b = -6+8 = 2= RHS
\n" ); document.write( "Therefore our values are correct.\r
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