document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=233734>Question 233734</A>: <I><SPAN STYLE=\"word-break: break-all;\"> PI need your help with this problem I am not sure how you would set it up. A recreation department plans to build a rectangular playground enclosed by 1000 meters of fence. If the length of the playground is 4 meters less than 3 times the width find the length and width of the playground. I think the best way to set it up is 1000=(2l-4+2wcubed)but not sure please help me. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #172484 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=172484\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A recreation department plans to build a rectangular playground enclosed by 1000 meters of fence. If the length of the playground is 4 meters less than 3 times the width find the length and width of the playground.\r<BR>\n" );
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document.write( "L = length of the playground<BR>\n" );
document.write( "W = width of the playground.\r<BR>\n" );
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document.write( "Perimeter of the playground is 1000 meters.\r<BR>\n" );
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document.write( "P = Perimeter of the playground.\r<BR>\n" );
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document.write( "P = 2L + 2W\r<BR>\n" );
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document.write( "1000 = 2L + 2W\r<BR>\n" );
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document.write( "Length of the playground is 4 meters less than 3 times the width.\r<BR>\n" );
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document.write( "L = 3*W - 4\r<BR>\n" );
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document.write( "Replace L with 3*W-4 to get:\r<BR>\n" );
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document.write( "1000 = 2L + 2W becomes:\r<BR>\n" );
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document.write( "1000 = 2 * (3W-4) + 2W which becomes:\r<BR>\n" );
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document.write( "1000 = 6W - 8 + 2W which becomes:\r<BR>\n" );
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document.write( "1000 = 8W - 8\r<BR>\n" );
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document.write( "Add 8 to both sides to get:\r<BR>\n" );
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document.write( "1008 = 8W\r<BR>\n" );
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document.write( "Divide both sides by 8 to get:\r<BR>\n" );
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document.write( "W = 126\r<BR>\n" );
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document.write( "If W = 126, then:\r<BR>\n" );
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document.write( "L = 3*W - 4 = 374\r<BR>\n" );
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document.write( "P = 1000 = 2L + 2W = 2*374 + 2*126 = 1000\r<BR>\n" );
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document.write( "L = 3*W - 4 = 3*126 - 4 = 374 is ok.\r<BR>\n" );
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document.write( "Perimeter equals 1000.<BR>\n" );
document.write( "L = 3W - 4\r<BR>\n" );
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document.write( "Everything looks good so the answer is:\r<BR>\n" );
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document.write( "L = 374<BR>\n" );
document.write( "W = 126\r<BR>\n" );
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document.write( " </SPAN>\n" );
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