document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=233680>Question 233680</A>: <I><SPAN STYLE=\"word-break: break-all;\"> one base of a trapezoid is three less than twice the length of the other base. The altitude of the trapezoid is 14 inches. if the area of the trapezoid is 63 square inches, find the length of each base  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #172461 by </B><A HREF=/tutors/aboutme.mpl?userid=mestrydilip><B>mestrydilip(13)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mestrydilip><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mestrydilip><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=172461\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Length of one base = x\r<BR>\n" );
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document.write( "Lenght of other base = 2x - 3\r<BR>\n" );
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document.write( "Altitude = 14\r<BR>\n" );
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document.write( "Area = 1/2 (sum of the bases) X Altitude\r<BR>\n" );
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document.write( "63 = 1/2 ( x + 2x - 3) X 14\r<BR>\n" );
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document.write( "63 = 1/2 (3x - 3) X 14\r<BR>\n" );
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document.write( "63 = 7 (3x - 3)\r<BR>\n" );
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document.write( "9 = 3x - 3\r<BR>\n" );
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document.write( "12 = 3x\r<BR>\n" );
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document.write( "x = 4\r<BR>\n" );
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document.write( "other base = 2x - 3 = 2(4)-3 = 8 - 3 = 5 </SPAN>\n" );
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