document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=233650>Question 233650</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a semicircular region, measured in meters, is numerically equal to its area, measured in square meters. The radius of the semicircle, measured in meters, is\r<BR>\n" );
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document.write( "a) 2/pi      b) ½   c)  pi   d)  1   e)  4/pi +2 \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #172452 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=172452\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a semicircular region, measured in meters, is numerically equal to its area, measured in square meters. The radius of the semicircle, measured in meters, is <BR>\n" );
document.write( "a) 2/pi b) ½ c) pi d) 1 e) 4/pi +2<BR>\n" );
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document.write( "Perimeter = (1/2)2(pi)r  + 2r = (pi)r + 2r = (2+(pi))r meters<BR>\n" );
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document.write( "Area = (pi)r^2 <BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "(2+(pi))r = (pi)r^2<BR>\n" );
document.write( "pi*r^2 - (2+pi)r = 0<BR>\n" );
document.write( "r(pi*r - (2+pi)) = 0<BR>\n" );
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document.write( "Non-zero solution:<BR>\n" );
document.write( "r = (2+pi)/pi<BR>\n" );
document.write( "r = (2/pi) = 1<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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