document.write( "Question 233614: The cost of producing an initial bicycle is £1200 and each successive bicycle there after cost £50 less than the last one. How many bicycles can be made for £10000?\r
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document.write( "I believe I know the formula, however because the Sn is 'less than' I cant seem to get to the answer!! \n" );
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Algebra.Com's Answer #172418 by stanbon(75887) ![]() You can put this solution on YOUR website! The cost of producing an initial bicycle is £1200 and each successive bicycle there after cost £50 less than the last one. How many bicycles can be made for £10000? \n" ); document.write( "I believe I know the formula, however because the Sn is 'less than' I cant seem to get to the answer!! \n" ); document.write( "------------------- \n" ); document.write( "Series: 1200 + 1150 + 1100 + ... \n" ); document.write( "S(n) < 10,000 \n" ); document.write( "--------------------- \n" ); document.write( "a = 1200 and d = -50 \n" ); document.write( "-------------------------- \n" ); document.write( "Solve: \n" ); document.write( "S(n) = (n/2)(a(1) + a(n)) \n" ); document.write( "10000 = (n/2)(1200 + a(n)) \n" ); document.write( "20000= (n)(1200 + 1200 +(n-1)(-50)) \n" ); document.write( "20000 = (n)(2400 -50n+50) \n" ); document.write( "20000 = n(2450 - 50n) \n" ); document.write( "-50n^2 +2450n - 20000 = 0 \n" ); document.write( "n^2 - 49n + 400 = 0 \n" ); document.write( "n = 38.65 or n = 10.35 \n" ); document.write( "---------------------------- \n" ); document.write( "Now consider the inequality: \n" ); document.write( "20000 < n(2450n-50n) \n" ); document.write( "n^2 -49n + 400 < 0 \n" ); document.write( "The parabola opens up so the \n" ); document.write( "solutions for the inequality are \n" ); document.write( "between the roots. \n" ); document.write( "10.35 < n < 38.65 \n" ); document.write( "=============================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |