document.write( "Question 233614: The cost of producing an initial bicycle is £1200 and each successive bicycle there after cost £50 less than the last one. How many bicycles can be made for £10000?\r
\n" ); document.write( "\n" ); document.write( "I believe I know the formula, however because the Sn is 'less than' I cant seem to get to the answer!!
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Algebra.Com's Answer #172418 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
The cost of producing an initial bicycle is £1200 and each successive bicycle there after cost £50 less than the last one. How many bicycles can be made for £10000?
\n" ); document.write( "I believe I know the formula, however because the Sn is 'less than' I cant seem to get to the answer!!
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\n" ); document.write( "Series: 1200 + 1150 + 1100 + ...
\n" ); document.write( "S(n) < 10,000
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\n" ); document.write( "a = 1200 and d = -50
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\n" ); document.write( "Solve:
\n" ); document.write( "S(n) = (n/2)(a(1) + a(n))
\n" ); document.write( "10000 = (n/2)(1200 + a(n))
\n" ); document.write( "20000= (n)(1200 + 1200 +(n-1)(-50))
\n" ); document.write( "20000 = (n)(2400 -50n+50)
\n" ); document.write( "20000 = n(2450 - 50n)
\n" ); document.write( "-50n^2 +2450n - 20000 = 0
\n" ); document.write( "n^2 - 49n + 400 = 0
\n" ); document.write( "n = 38.65 or n = 10.35
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\n" ); document.write( "Now consider the inequality:
\n" ); document.write( "20000 < n(2450n-50n)
\n" ); document.write( "n^2 -49n + 400 < 0
\n" ); document.write( "The parabola opens up so the
\n" ); document.write( "solutions for the inequality are
\n" ); document.write( "between the roots.
\n" ); document.write( "10.35 < n < 38.65
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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