document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=233492>Question 233492</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do I solve x to the -3 power in parenthesis and a 2 outside the parenthesis? I know for the negative exponent I make it 1/x to the 3rd but how do I square a fraction? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #172373 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=172373\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how do I solve x to the -3 power in parenthesis and a 2 outside the parenthesis? I know for the negative exponent I make it 1/x to the 3rd but how do I square a fraction?<BR>\n" );
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document.write( "(x^-3)^2<BR>\n" );
document.write( "(1/x^3)^2<BR>\n" );
document.write( "= (1/x^3)*(1/x^3) = 1/x^6<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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