document.write( "Question 233474: The revenue for the sale of x items is determined by the formula R = 50 x – x2. The cost of producing x items is given by the formula C = 2x +40. For what value of x is the profit positive? (Profit = revenue minus cost)\r
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document.write( "Do I set it up like this ? 50x-x^2=2x+40 \n" );
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Algebra.Com's Answer #172333 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! R = 50 x – x2. \n" ); document.write( "C = 2x +40. \n" ); document.write( "R-C>0 IS THE PROFIT EQUATION. \n" ); document.write( "------------------------------------- \n" ); document.write( "50X-X^2-(2X+40)>0 \n" ); document.write( "50X-X^2-2X-40>0 \n" ); document.write( "-X^2+48X-40>0 \n" ); document.write( "X^2-48X+40>0 \n" ); document.write( " \n" ); document.write( "X=(48+-SQRT[-48^2-4*1*40])/2*1 \n" ); document.write( "X=(48+-SQRT[2,304-160)/2 \n" ); document.write( "X=(48+-SQRT2144)/2 \n" ); document.write( "X=(48+-46.3)/2 \n" ); document.write( "X=(48+46.3)/2 \n" ); document.write( "X=94.3/2 \n" ); document.write( "X=47.15 ANS. \n" ); document.write( "THIS SAYS THAT AT LEAST 48 UNITS MUST BE SOLD TO HAVE A PROFIT.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |