document.write( "Question 233438: if you could can you please explain to me how to solve this math problem? thank you soooo much!! (:\r
\n" ); document.write( "\n" ); document.write( "(I stands for absolute value since i dont have the actual symbol)\r
\n" ); document.write( "\n" ); document.write( "I x I + 4 (is less than) 9
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Algebra.Com's Answer #172298 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
You can use the function term of abs(x) to indicate the absolute value of x.\r
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\n" ); document.write( "\n" ); document.write( "Otherwise, it's the symbol above the backslash which is to the right of the letter P three keys to the right on my keyboard.\r
\n" ); document.write( "\n" ); document.write( "It looks like a broken line going straight up and down with a space in the middle. When you hit the key, it shows up as | which is not broken in the middle by a space.\r
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\n" ); document.write( "\n" ); document.write( "Anyway .....................\r
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\n" ); document.write( "\n" ); document.write( "abs(x) + 4 < 9\r
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\n" ); document.write( "\n" ); document.write( "subtract 4 from both sides of this equation to get:\r
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\n" ); document.write( "\n" ); document.write( "abs(x) < 9-4 which becomes abs(x) < 5\r
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\n" ); document.write( "\n" ); document.write( "by definition, abs(x) < 5 means that:\r
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\n" ); document.write( "\n" ); document.write( "x < 5 if x is positive.\r
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\n" ); document.write( "\n" ); document.write( "-x < 5 if x is negative.\r
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\n" ); document.write( "\n" ); document.write( "solve for x < 5 to get x < 5\r
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\n" ); document.write( "\n" ); document.write( "take -x < 5 and multiply both sides of this equation by -1 to get:\r
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\n" ); document.write( "\n" ); document.write( "x > -5\r
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\n" ); document.write( "\n" ); document.write( "your answer is that x is either < 5 or x > -5\r
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\n" ); document.write( "\n" ); document.write( "this can be written as -5 < x < 5\r
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\n" ); document.write( "\n" ); document.write( "to prove, plug good and bad values of into the original equation to see what happens.\r
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\n" ); document.write( "\n" ); document.write( "take x = -5,-4,0,4,5\r
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\n" ); document.write( "\n" ); document.write( "x = -5,5 are outside of the limits so the answer should be false.
\n" ); document.write( "x = -4,0,4 are inside the limits so the answer should be true.\r
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\n" ); document.write( "\n" ); document.write( "Let y = abs(x) + 4 < 9\r
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\n" ); document.write( "\n" ); document.write( "when x = -5, y = 9 not < 9 so this is good because -5 is outside of the limits.
\n" ); document.write( "when x = -4, y = 8 < 9 so this is good because -5 is inside the limits.
\n" ); document.write( "when x = 0, y = 4 < 9 so this is good because 0 is inside the limits.
\n" ); document.write( "when x = 4, y = 8 < 9 so this is good because 4 is inside the limits.
\n" ); document.write( "when x = 5, y = 9 not < 9 so this is good because 5 is outside the limits.\r
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\n" ); document.write( "\n" ); document.write( "Your answer is:\r
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\n" ); document.write( "\n" ); document.write( "-5 < x < 5\r
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