document.write( "Question 233396: The difference between the hypotenuse and the other two sides of a right triangle are respectively 8feet and 4 feet. the perimeter of the triangle is\r
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Algebra.Com's Answer #172290 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
The difference between the hypotenuse and the other two sides of a right triangle are respectively 8 feet and 4 feet. the perimeter of the triangle is
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document.write( "Shorter leg = a\r\n" );
document.write( "Longer leg = b\r\n" );
document.write( "Hypotenuse = c\r\n" );
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document.write( "Hypotenuse - shorter leg = 8, so\r\n" );
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document.write( "\"c+-+a+=+8\"\r\n" );
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document.write( "Hypotenuse - longer leg = 4, so\r\n" );
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document.write( "\"c+-+b+=+4\"\r\n" );
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document.write( "Since it is a right triangle, the Pythagorean theorem\r\n" );
document.write( "holds, so\r\n" );
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document.write( "\"a%5E2%2Bb%5E2=c%5E2\"\r\n" );
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document.write( "So we have the system of three equations in three unknowns:\r\n" );
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document.write( "\"system%28c+-+a+=+8%2Cc+-+b+=+4%2Ca%5E2%2Bb%5E2=c%5E2%29\"\r\n" );
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document.write( "Solve the first one for a, and the second one for b:\r\n" );
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document.write( "\"a=c-8\", \"b=c-4\"\r\n" );
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document.write( "Substitute in the third equation\r\n" );
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document.write( "\"a%5E2%2Bb%5E2=c%5E2\"\r\n" );
document.write( "\"%28c-8%29%5E2%2B%28c-4%29%5E2=c%5E2\"\r\n" );
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document.write( "Can you solve that for c?  If not post again asking how.\r\n" );
document.write( "It comes out as a factorable quadratic equation. \r\n" );
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document.write( "You get two solutions for c, \"c=4\", and \"c=20\"\r\n" );
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document.write( "We must discard the hypotenuse of 4, since it would be\r\n" );
document.write( "impossible for c, the longest side to differ from the\r\n" );
document.write( "longer leg by 8.\r\n" );
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document.write( "Therefore \"c=20\"\r\n" );
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document.write( "Substituting in  \r\n" );
document.write( "\"a=c-8\" and \"b=c-4\"\r\n" );
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document.write( "\"a=20-8\" and \"b=20-4\"\r\n" );
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document.write( "or\r\n" );
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document.write( "\"a=12\", \"b=16\"\r\n" );
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document.write( "So the perimeter = \"a%2Bb%2Bc=12%2B16%2B20=48\", choice a).\r\n" );
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document.write( "Edwin
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