document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=233354>Question 233354</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you help me\r<BR>\n" );
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document.write( "Simplify Assume that no denominator is zero and that 0^0 in not considered\r<BR>\n" );
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document.write( "(4r^7)^4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #172248 by </B><A HREF=/tutors/aboutme.mpl?userid=unlockmath><B>unlockmath(1688)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=unlockmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=unlockmath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=172248\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (4r^7)^4<BR>\n" );
document.write( "Hello, <BR>\n" );
document.write( "Let's expand this out and it'll make sense then. <BR>\n" );
document.write( "We could write it as:<BR>\n" );
document.write( "(4r^7)(4r^7)(4r^7)(4r^7) (Then let's multiply the 4's first which gives us 256. Now let's find how many r^7's there are. That total 28. So now we can write it as:<BR>\n" );
document.write( "256r^28<BR>\n" );
document.write( "A faster way is multiply 7 times 4 to give you the power and 4 mutiplied by itself 4 times. In other words (4)(4)(4)(4)= 256<BR>\n" );
document.write( "RJ Toftness<BR>\n" );
document.write( "www.math-unlock.com </SPAN>\n" );
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