document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=233349>Question 233349</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a parking meter accepts only quarters and dollars.there are 31 coins value of 20.50 how many quarters and dollars are there </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #172245 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=172245\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a parking meter accepts only quarters and dollars.there are 31 coins value of 20.50 how many quarters and dollars are there<BR>\n" );
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document.write( "Q + D = 31 (# of coins)<BR>\n" );
document.write( "25Q + 100D = 2050 (value of coins)<BR>\n" );
document.write( "D = 31-Q<BR>\n" );
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document.write( "25Q + 100D = 2050<BR>\n" );
document.write( "25Q + 100*(31-Q) = 2050<BR>\n" );
document.write( "25Q + 3100 - 100Q = 2050<BR>\n" );
document.write( "-75Q = -1050<BR>\n" );
document.write( "Q = 14<BR>\n" );
document.write( "D = 17<BR>\n" );
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