document.write( "Question 233259: Flight 725 left New York at 10:28 a.m. flying north. Flight 245 left from the same airport at 11:18 a.m. flying south at one hundred twenty kph less than three times the speed of flight 725. At 1:06 p.m. they are 1,030 kilometers apart. What is the average rate of speed for Flight 245?\r
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document.write( "I have no clues on how to solve this problem.
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document.write( "Thanks for your answer. \n" );
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Algebra.Com's Answer #172194 by edjones(8007)![]() ![]() You can put this solution on YOUR website! Flight 725 left New York at 10:28 a.m. flying north. Flight 245 left from the same airport at 11:18 a.m. flying south at one hundred twenty kph less than three times the speed of flight 725. At 1:06 p.m. they are 1,030 kilometers apart. What is the average rate of speed for Flight 245?\r \n" ); document.write( "\n" ); document.write( "d=st d=dist., s=speed, t=time \n" ); document.write( "1:06 pm=13:06 (24 hr clock) \n" ); document.write( "13:06-10:28=2:38=2.633 hr time of 1st flight \n" ); document.write( "13:06-11:18=1:48=1.800 hr time of 2nd flight \n" ); document.write( "s=speed of 1st flight, 3s-120=speed of the 2nd flight \n" ); document.write( "s*t of the 1st + s* t of the 2nd = total distance traveled \n" ); document.write( "2.633s+1.8(3s-120)=1030 \n" ); document.write( "2.633s+5.4s-216=1030 \n" ); document.write( "8.033s=1246 \n" ); document.write( "=155.11 k/h \n" ); document.write( "(3*155.11)-120 \n" ); document.write( "=345.331 k/h speed of flight 245. \n" ); document.write( " |