document.write( "Question 233167: please help me solve this problem\r
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\n" ); document.write( "\n" ); document.write( "A rectangular garden is 15 ft longer than it is wide. Its area is 4500 feet squared. What are its dimensions?
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Algebra.Com's Answer #172141 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
L = length
\n" ); document.write( "W = width\r
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\n" ); document.write( "\n" ); document.write( "L = W + 15\r
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\n" ); document.write( "\n" ); document.write( "A = area = L*W\r
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\n" ); document.write( "\n" ); document.write( "L*W = 4500\r
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\n" ); document.write( "\n" ); document.write( "Since L = W + 15, this becomes:\r
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\n" ); document.write( "\n" ); document.write( "(W + 15) * W = 4500\r
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\n" ); document.write( "\n" ); document.write( "This becomes W^2 + 15*W = 4500\r
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\n" ); document.write( "\n" ); document.write( "Subtract 4500 from both sides to get W^2 + 15*W - 4500 = 0\r
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\n" ); document.write( "\n" ); document.write( "Factor to get (W - 60) * (W + 75) = 0\r
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\n" ); document.write( "\n" ); document.write( "This makes W = 60 or W = -75\r
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\n" ); document.write( "\n" ); document.write( "W can't be negative so W = 60 or not at all.\r
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\n" ); document.write( "\n" ); document.write( "Take W = 60\r
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\n" ); document.write( "\n" ); document.write( "This makes L = W + 15 = 75\r
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\n" ); document.write( "\n" ); document.write( "60 * 75 = 4500 so the area is good.\r
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\n" ); document.write( "\n" ); document.write( "L = 15 more than W so L and W are ok.\r
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\n" ); document.write( "\n" ); document.write( "Your answer is that the dimensions are:\r
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\n" ); document.write( "\n" ); document.write( "Length = 75 feet
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\n" ); document.write( "Area = 4500 square feet\r
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