document.write( "Question 233123: A charter company will provide a plane for a fare of $200 each for 80 or fewer passengers. For each passenger in excess of 80, the fare is decreased by $2.00 per person for everyone. What number of passengers would produce the greatest revenue for the company. \n" ); document.write( "
Algebra.Com's Answer #172102 by stanbon(75887)\"\" \"About 
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A charter company will provide a plane for a fare of $200 each for 80 or fewer passengers.
\n" ); document.write( "For each passenger in excess of 80, the fare is decreased by $2.00 per person for everyone.
\n" ); document.write( "What number of passengers would produce the greatest revenue for the company.
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\n" ); document.write( "Equation:
\n" ); document.write( "Revenue(x) = (80+x)(200-2x)
\n" ); document.write( "R(x) = -2x^2 + 40x + 16000
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\n" ); document.write( "Maximum Revenue occurs when x = -b/2a = -40/(-4) = 10
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\n" ); document.write( "80+10 = 90 would be the number of passengers needed to maximize Revenue.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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