document.write( "Question 233123: A charter company will provide a plane for a fare of $200 each for 80 or fewer passengers. For each passenger in excess of 80, the fare is decreased by $2.00 per person for everyone. What number of passengers would produce the greatest revenue for the company. \n" ); document.write( "
Algebra.Com's Answer #172102 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A charter company will provide a plane for a fare of $200 each for 80 or fewer passengers. \n" ); document.write( "For each passenger in excess of 80, the fare is decreased by $2.00 per person for everyone. \n" ); document.write( "What number of passengers would produce the greatest revenue for the company. \n" ); document.write( "------------------ \n" ); document.write( "Equation: \n" ); document.write( "Revenue(x) = (80+x)(200-2x) \n" ); document.write( "R(x) = -2x^2 + 40x + 16000 \n" ); document.write( "--- \n" ); document.write( "Maximum Revenue occurs when x = -b/2a = -40/(-4) = 10 \n" ); document.write( "--------------------- \n" ); document.write( "80+10 = 90 would be the number of passengers needed to maximize Revenue. \n" ); document.write( "============================================================================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |