document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=30375>Question 30375</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Question:<BR>\n" );
document.write( "Solve:<BR>\n" );
document.write( "^3 sqrt x^2-4x+2=^3 sqrt x+2\r<BR>\n" );
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document.write( "POssible Solutions:<BR>\n" );
document.write( "(A) 0, 5<BR>\n" );
document.write( "(B) 1/2, 5<BR>\n" );
document.write( "(C) 0, 11/2<BR>\n" );
document.write( "(D) 1/2, 11/2\r<BR>\n" );
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document.write( "Please be specific as to which letter answer is correct please<BR>\n" );
document.write( "Thanks for your help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #17204 by </B><A HREF=/tutors/aboutme.mpl?userid=sdmmadam@yahoo.com><B>sdmmadam@yahoo.com(530)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sdmmadam@yahoo.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=17204\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ^3 sqrt x^2-4x+2=^3 sqrt x+2<BR>\n" );
document.write( "Probably the question is <BR>\n" );
document.write( "[sqrt (x^2-4x+2)]^3 = [sqrt (x+2)]^3  ----(1)<BR>\n" );
document.write( "This implies<BR>\n" );
document.write( "(x^2-4x+2) = (x+2)<BR>\n" );
document.write( "x^2-4x-x+2-2 = 0 (grouping like terms)<BR>\n" );
document.write( "x^2-5x = 0<BR>\n" );
document.write( "x(x-5) = 0<BR>\n" );
document.write( "x =0 or  (x-5)=0 which gives x = 5<BR>\n" );
document.write( "Answer: x = 0 or x = 5<BR>\n" );
document.write( "which is your choice (A)\r<BR>\n" );
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document.write( "Let us evolve a model out of this<BR>\n" );
document.write( "[sqrt(p)]^3 =[sqrt(q)]^3<BR>\n" );
document.write( "[(p)^(1/2)]^3= [(q)^(1/2)]^3<BR>\n" );
document.write( "[(p)^(3/2)]= [(q)^(3/2)]  (using [(a)^m]^n =[(a)^(mn) &#8212;&#8212;(*)] )<BR>\n" );
document.write( "Now raising both the sides to the power (2/3)<BR>\n" );
document.write( "[(p)^(3/2)]^(2/3)= [(q)^(3/2)]^(2/3)<BR>\n" );
document.write( "{(p)^[(3/2)X(3/2)]}= {(q)^[(3/2)X(3/2)]}<BR>\n" );
document.write( "[(p)^1]= [(q)^1] ((using (*) )<BR>\n" );
document.write( "That is   p = q<BR>\n" );
document.write( "Note: The above steps if we go through repeatedly then <BR>\n" );
document.write( "we will be in a position to just observe and conclude </SPAN>\n" );
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