document.write( "Question 232939: logx(49)=2 \n" ); document.write( "
Algebra.Com's Answer #172028 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Read it this way: \"\"x\" is a base which, if raised
\n" ); document.write( "to the exponent \"2\" will give me \"49\"\"
\n" ); document.write( "Now rewrite the equation this way
\n" ); document.write( "\"x%5E2+=+49\"
\n" ); document.write( "Now take the square root of both sides
\n" ); document.write( "\"x+=+7\" answer
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