document.write( "Question 30462: (m) Question: 3 sqrt 9x-4 =3 sqrt 2x+9\r
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document.write( "(A) -8/13
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document.write( "(B) 13/7
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document.write( "(C) 2
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document.write( "(D) -7/13\r
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document.write( "Thank you very much! \n" );
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Algebra.Com's Answer #17202 by sdmmadam@yahoo.com(530)![]() ![]() ![]() You can put this solution on YOUR website! The problem may be as follows: \n" ); document.write( " [sqrt (9x-4)]^3 =[sqrt (2x+9)]^3 ----(1) \n" ); document.write( "This implies (9x-4) = (2x+9) \n" ); document.write( "(how? see the model below for you to learn and understand. \n" ); document.write( "You need not show those steps if the above problem \n" ); document.write( "is a 1 mark question!) \n" ); document.write( "9x-2x= 9+4 \n" ); document.write( "7x= 13 \n" ); document.write( "x = 13/7 \n" ); document.write( "Answer: x = 13/7 \n" ); document.write( "which is choice (B) 13/7\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Note:Let us evolve a model out of this \n" ); document.write( "[sqrt(p)]^3 =[sqrt(q)]^3 \n" ); document.write( "[(p)^(1/2)]^3= [(q)^(1/2)]^3 \n" ); document.write( "[(p)^(3/2)]= [(q)^(3/2)] (using [(a)^m]^n =[(a)^(mn) ----(*)] ) \n" ); document.write( "Now raising both the sides to the power (2/3) \n" ); document.write( "[(p)^(3/2)]^(2/3)= [(q)^(3/2)]^(2/3) \n" ); document.write( "{(p)^[(3/2)X(3/2)]}= {(q)^[(3/2)X(3/2)]} \n" ); document.write( "[(p)^1]= [(q)^1] ((using (*) ) \n" ); document.write( "That is p = q \n" ); document.write( "Note: The above steps if we go through repeatedly then \n" ); document.write( "we will be in a position to just observe and conclude \n" ); document.write( " \n" ); document.write( " |