document.write( "Question 232823: Please help me with this problem: 4+|3-(x/3)|>=9
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document.write( "I get x<=-6 and x>=48 my professor says that the 48 should be 24 and i just don't understand why! \n" );
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Algebra.Com's Answer #172003 by Alan3354(69443) You can put this solution on YOUR website! 4+|3-(x/3)|>=9 \n" ); document.write( "|3-(x/3)| = 5 \n" ); document.write( "-------------- \n" ); document.write( "3-(x/3) = 5 \n" ); document.write( "x/3 = -2 \n" ); document.write( "x = -6 \n" ); document.write( "----------- \n" ); document.write( "(x/3)-3 = 5 \n" ); document.write( "x/3 = 8 \n" ); document.write( "x = 24 \n" ); document.write( "-------- \n" ); document.write( "How did you get 48? \n" ); document.write( "------------------- \n" ); document.write( "I get x<=-6 and x>=48 my professor says that the 48 should be 24 and i just don't understand why \n" ); document.write( " |