document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=232882>Question 232882</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the perimeter of a rectangular pool is 140 yd. if the length is 20 yd less than twice the width, find the length and the width </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #171979 by </B><A HREF=/tutors/aboutme.mpl?userid=mando271><B>mando271(42)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mando271><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=171979\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> i'll use L for length and W for width.\r<BR>\n" );
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document.write( "you are given that L=2W-20.\r<BR>\n" );
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document.write( "and you need 2 lengths and 2 width to form a rectangle, so.\r<BR>\n" );
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document.write( "2W+2(2W-20)=140\r<BR>\n" );
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document.write( "2W+4W-40=140\r<BR>\n" );
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document.write( "6W=180\r<BR>\n" );
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document.write( "W=30\r<BR>\n" );
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document.write( "so width equals 30, now plug this in to the 1st equation to solve for L\r<BR>\n" );
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document.write( "L=2(30)-20\r<BR>\n" );
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document.write( "L=60-20\r<BR>\n" );
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document.write( "L=40 </SPAN>\n" );
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