document.write( "Question 232876: Suppose household incomes in Indiana Co have a mean of $48,000 and a standard deviation of $18,000. What is the probability that a random sample of 100 households with a mean income below $45,000?
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Algebra.Com's Answer #171973 by stanbon(75887)\"\" \"About 
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Suppose household incomes in Indiana Co have a mean of $48,000 and a standard deviation of $18,000. What is the probability that a random sample of 100 households with a mean income below $45,000?
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\n" ); document.write( "z(45000) = (45000-48000)/[18000/(sqrt(100)]
\n" ); document.write( "= -3000/(1800)
\n" ); document.write( "= -1.66667
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\n" ); document.write( "P(x < 45000) = P(z < -1.66667) = 0.04779,,,\r
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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