document.write( "Question 232816: Find four consecutive even integers so that the sum of the first three is 2 more than twice the fourth
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Algebra.Com's Answer #171970 by mando271(42)\"\" \"About 
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let the 1st integer be x.\r
\n" ); document.write( "\n" ); document.write( "since they have to be consecutive, the 2nd will be x+2, the 3rd x+4 and the 4th x+6.\r
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\n" ); document.write( "\n" ); document.write( "x+x+2+x+4 = 2(x+6)+2, now solve for x\r
\n" ); document.write( "\n" ); document.write( "3x+6 = 2x+12+2
\n" ); document.write( "x=8\r
\n" ); document.write( "\n" ); document.write( "so substituting 8 for x. the integers are:\r
\n" ); document.write( "\n" ); document.write( "8, 10, 12, 14
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