document.write( "Question 232845: find:\r
\n" ); document.write( "\n" ); document.write( "2x/(x^2-9) + (1-2x)/(x^2-4x+3) \n" ); document.write( "
Algebra.Com's Answer #171965 by eggsarecool(46)\"\" \"About 
You can put this solution on YOUR website!
I am assuming you want this solved for 0
\n" ); document.write( "\"2x%2F%28x%5E2-9%29+%2B+%281-2x%29%2F%28x%5E2-4x%2B3%29=0\" So first we need a common denominator
\n" ); document.write( "We will start by factoring the current denominators.
\n" ); document.write( "\"2x%2F%28x%2B3%29%28x-3%29%2B%281-2x%29%2F%28x-3%29%28x-1%29=0\"
\n" ); document.write( "Now for the common denominator.
\n" ); document.write( " Now your denominator cannot equal to zero since you are not allowed to divide by 0. so x cannot equal to 1, 3, or -3.
\n" ); document.write( "Since the bottom cannot equal 0 the only time the fraction will equal 0 is when the numerator equals 0.
\n" ); document.write( "Now we multiply out the numerator.
\n" ); document.write( "\"%282x%5E2-2x%2Bx%2B3-2x%5E2-6x%29%2F%28x%2B3%29%28x-3%29%28x-1%29=0\"
\n" ); document.write( "Next we combine like terms.
\n" ); document.write( "\"%28-7x%2B3%29%2F%28x%2B3%29%28x-3%29%28x-1%29=0\"
\n" ); document.write( "Now we set the numerator equal to 0 and solve.
\n" ); document.write( "\"-7x%2B3=0\" Add 7x to both sides.
\n" ); document.write( "\"7x=3\" Divide both sides by 7.
\n" ); document.write( "\"x=3%2F7\"
\n" ); document.write( " \n" ); document.write( "
\n" );