document.write( "Question 232846: I need help with COMPLETELY factoring out the polynomial 3x3-12x \n" ); document.write( "
Algebra.Com's Answer #171961 by eggsarecool(46)\"\" \"About 
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I need help with COMPLETELY factoring out the polynomial \"3x%5E3-12x\"
\n" ); document.write( "Ok first step would be to factor out \"3x\" which leaves us with
\n" ); document.write( "\"3x%28x%5E2-4%29\" Now we can use the differance of squares formula which says that \"a%5E2-b%5E2=%28a-b%29%28a%2Bb%29\"
\n" ); document.write( "For us \"a=x\" and \"b=-2\"
\n" ); document.write( "This gives us \"3x%28x%5E2-4%29=3x%28x%2B2%29%28x-2%29\" we factored the \"x%5E2-4\" using difference of squares.
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