document.write( "Question 30534: a)given that 3 + 2log2 x= log2 y show that y=8x2\r
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document.write( "b)Find the roots α and β where α<β of the equation\r
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document.write( "3+ 2log2 x = log2 (14x-3)\r
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document.write( "c)Show that log2 α = -2\r
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document.write( "d)calculate log2 β, giving your answer to 3sf.\r
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Algebra.Com's Answer #17190 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! a)given that 3 + 2log2 x= log2 y show that y=8x2 \n" ); document.write( "3+2LOG(X)/LOG(2) = LOG(Y)/LOG(2)...SINCE LOG(X) TO BASE A = LOG(X)/LOG(A)..TO ANY COMMON BASE. \n" ); document.write( "3LOG(2)+2LOG(X)=LOG(Y) \n" ); document.write( "LOG(2^3)+LOG(X^2)=LOG(Y)...SINCE LOG(X^N)=N*LOG(X) \n" ); document.write( "LOG(8)+LOG(X^2)=LOG(Y) \n" ); document.write( "LOG(8X^2)=LOG(Y)...SINCE LOG(X*Y) = LOG(X)+LOG(Y) \n" ); document.write( "TAKING ANTILOGS \n" ); document.write( "Y=8X^2 \n" ); document.write( "b)Find the roots α and β where α<β of the equation \n" ); document.write( "3+ 2log2 x = log2 (14x-3) \n" ); document.write( "USING RESULT OF ABOVE PROBLEM ,OR PROCEEDING SAME WAY AS ABOVE,WE GET.. \n" ); document.write( "14X-3=8X^2 \n" ); document.write( "8X^2-14X+3=0 \n" ); document.write( "8X^2-12X-2X+3=0 \n" ); document.write( "4X(2X-3)-1(2X-3)=0 \n" ); document.write( "(2X-3)(4X-1)=0 \n" ); document.write( "ALPHA=1/4....AND.....BETA=3/2.... \n" ); document.write( "c)Show that log2 α = -2 \n" ); document.write( "LOG(1/4)TO BASE 2 =LOG(1/2^2) TO BASE 2.. \n" ); document.write( "LOG(2^-2)TO BASE 2 = -2\r \n" ); document.write( "\n" ); document.write( "d)calculate log2 β, giving your answer to 3sf. \n" ); document.write( "LOG(3/2) TO BASE 2.=LOG(1.5)/LOG(2) \n" ); document.write( "=0.5849 =0.585\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |