document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=232738>Question 232738</A>: <I><SPAN STYLE=\"word-break: break-all;\"> You have a solution that is 50% alcohol and a solution that is 80% alcohol. How much of each do you need to mix to get 3 gallons of a solution that is 60% alcohol? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #171897 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=171897\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">     You have a solution that is 50% alcohol and a solution that is 80% alcohol. How much of each do you need to mix to get 3 gallons of a solution that is 60% alcohol?<BR>\n" );
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document.write( "Let x = amount of 50% alcohol<BR>\n" );
document.write( "then<BR>\n" );
document.write( "3-x = amount of 80% alcohol<BR>\n" );
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document.write( ".50x + .80(3-x) = .60(3)<BR>\n" );
document.write( ".50x + 2.4 - .80x = 1.8<BR>\n" );
document.write( "2.4 -.30x = 1.8<BR>\n" );
document.write( "-.30x = -0.6<BR>\n" );
document.write( "x = 2 gallons (50% alcohol)<BR>\n" );
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document.write( "80% alcohol:<BR>\n" );
document.write( "3-x = 3-2 = 1 gallon (80% alcohol)<BR>\n" );
document.write( " </SPAN>\n" );
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