document.write( "Question 30479: (m) Question:
\n" ); document.write( "^3 sqrt 9x-4=^3 sqrt 2x+9\r
\n" ); document.write( "\n" ); document.write( "Answers:
\n" ); document.write( "(a) -8/13
\n" ); document.write( "(b) 13/7
\n" ); document.write( "(c) 2
\n" ); document.write( "(d) -7/13\r
\n" ); document.write( "\n" ); document.write( "Please be specific as to which letter answer is correct. thanks for your help!
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Algebra.Com's Answer #17189 by sdmmadam@yahoo.com(530)\"\" \"About 
You can put this solution on YOUR website!
^3 sqrt 9x-4=^3 sqrt 2x+9
\n" ); document.write( "Probably the question is
\n" ); document.write( "[sqrt(9x-4)]^3 = [sqrt(2x+9)]^3
\n" ); document.write( "This means [(9x-4)^(1/2)]^3 = [(2x+9)^(1/2)]^3 (as sqrt(p) means (p)^(1/2) )
\n" ); document.write( "[(9x-4)^(3/2)]= [(2x+9)^(3/2)] (using [(a)^m]^n =[(a)^(mn) ----(*)]
\n" ); document.write( "Now raising both the sides to the power (2/3)
\n" ); document.write( "[(9x-4)^(3/2)]^(2/3)= [(2x+9)^(3/2)]^(2/3)
\n" ); document.write( "{(9x-4)^[(3/2)X(3/2)]}= {(2x+9)^[(3/2)X(3/2)]} (using (*) )
\n" ); document.write( "That is (9x-4)^1 = (2x+9)^1
\n" ); document.write( "That is (9x-4) = (2x+9)
\n" ); document.write( "9x-2x= 9+4 (grouping like terms)
\n" ); document.write( "7x = 13
\n" ); document.write( "x = 13/7
\n" ); document.write( "Answer: x = (13/7)
\n" ); document.write( "which is your choice (b)\r
\n" ); document.write( "\n" ); document.write( "Note: If you can feel the nerve of the problem the idea behind it is very simple and you can see it in your mental eye.
\n" ); document.write( "Keep staring at the steps and absorb the concept!\r
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