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You can put this solution on YOUR website!
Probably the problem is
\n" ); document.write( "e^x = 4----(1)
\n" ); document.write( "Here the base is e, the power is x and the number is 4
\n" ); document.write( "Therefore by definition that log(of a positive quantity N) to a given base b is the power p to which the base b has to be raised to give the number N
\n" ); document.write( "Therefore x = log[e](4)
\n" ); document.write( "Answer: x = log[e](4)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Note: If you do not understand how to apply the definition
\n" ); document.write( "you may proceed as follows too
\n" ); document.write( "Taking log on both sides of (1) (base e)
\n" ); document.write( "log(e^x) =log(4)
\n" ); document.write( "xlog[e](e) = log[e](4) (using log[b](m^n) = nlog[b](m) )
\n" ); document.write( "That is xX1 = log[e](4)
\n" ); document.write( "[since log(any positive quantity) to the same base is 1]
\n" ); document.write( "That is x = log[e](4)
\n" ); document.write( "Answer: x = log[e](4)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Note: Practising the definition and writing down the answer in a jiffy will really help
\n" ); document.write( "Examples
\n" ); document.write( "1)log[10](100)= x
\n" ); document.write( "means 100 = 10^x = 10^2 and therefore x = 2
\n" ); document.write( "2)log[5](125) = t
\n" ); document.write( "means 125= 5^x = 5^3 and therefore x = 3
\n" ); document.write( "3)log[2](y) = 5
\n" ); document.write( "means y = 2^5 = 32
\n" ); document.write( "4)log[3](t) = 4
\n" ); document.write( "means t = 3^4 = 81 \n" ); document.write( "