document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=232644>Question 232644</A>: <I><SPAN STYLE=\"word-break: break-all;\"> is i had to solve for y what would x+y=-3  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #171866 by </B><A HREF=/tutors/aboutme.mpl?userid=unlockmath><B>unlockmath(1688)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=unlockmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=unlockmath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=171866\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hello, <BR>\n" );
document.write( "To solve for y in the equation x + y = -3, we need to get y by itself on one side of the equal sign. Here's how you do it. \r<BR>\n" );
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document.write( "          You subtract x on both sides of the equal sign. (remember,  <BR>\n" );
document.write( "                    whatever you do on one side of the equal sign you must do on <BR>\n" );
document.write( "                    one the other side.)<BR>\n" );
document.write( "x - x + y = -3 -x   (You see, x - x is zero therefore leaves y all alone.) \r<BR>\n" );
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document.write( "y = -3 - x          (Here's your answer)<BR>\n" );
document.write( "RJ Toftness<BR>\n" );
document.write( "www.math-unlock.com  </SPAN>\n" );
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