document.write( "Question 232588: Robert is now 1/2 his dad's age. Twelve years ago, robert was 1/3 his dad's age.
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document.write( "Find both their ages now? Can you please help. I messed 4 days of school because of the flu. \n" );
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Algebra.Com's Answer #171865 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! Dad=x \n" ); document.write( "Robert=x/2 \n" ); document.write( "x/2-12=x/3 \n" ); document.write( "x/2-x/3=12 \n" ); document.write( "(3x-2x)/6=12 \n" ); document.write( "x/6=12 \n" ); document.write( "x=72 age of Dad now. \n" ); document.write( "72/2=36 Robert's age now. \n" ); document.write( "Proof: \n" ); document.write( "36-12=72/3 \n" ); document.write( "24=24 \n" ); document.write( " |