document.write( "Question 232636: write an equation of the line that passes through (2,3) and perpendicular to 4x+5y=10 \n" ); document.write( "
Algebra.Com's Answer #171859 by Alan3354(69443)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "write an equation of the line in standard form that is perpendicular to 2x+6y=-4 and pass through (-1,-1)
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\n" ); document.write( "1st, find the slope, m1, of 2x+6y = -4 by putting it in slope-intercept form. (That means solve for y)
\n" ); document.write( "2x+6y = -4
\n" ); document.write( "x+3y = -2
\n" ); document.write( "3y = -x - 2
\n" ); document.write( "y = (-1/3)x - 2
\n" ); document.write( "m1 = -1/3
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\n" ); document.write( "The slope of lines perpendicular is the negative inverse of m1, = +3
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\n" ); document.write( "Use y = mx + b and the point to find b.
\n" ); document.write( "-1 = 3*-1 + b
\n" ); document.write( "b = 2
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\n" ); document.write( "--> y = 3x + 2 is thru (-1,-1) and perpendicular to 2x+6y = -4
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