document.write( "Question 232569: you have total of 50 coins in your pocket.you only quarters and dimes and the total value $ is 11.00 how many of each coin do you have \r
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document.write( "this what i was trying to do: 25q+10d=50
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document.write( " 25q+10(d-50)=50
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document.write( " 25q+10d+500=50
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document.write( " 25q+10d=50
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document.write( " 15=50
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document.write( " x3
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document.write( "not sure if its right \n" );
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Algebra.Com's Answer #171840 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! you have total of 50 coins in your pocket.you only quarters and dimes and the total value $ is 11.00 \n" ); document.write( " how many of each coin do you have \r \n" ); document.write( "\n" ); document.write( "You have the equations mixed up \n" ); document.write( ": \n" ); document.write( "Total coin equation \n" ); document.write( "q + d = 50 \n" ); document.write( "or \n" ); document.write( "d = (50-q); use this for substitution \n" ); document.write( ": \n" ); document.write( "and \n" ); document.write( "total value equation \n" ); document.write( ".25q + .10d = 11.00 \n" ); document.write( ": \n" ); document.write( "Substitute (50-q) for d, find q \n" ); document.write( ".25q + .10(50-q) = 11 \n" ); document.write( ": \n" ); document.write( ".25q + 5 - .10q = 11 \n" ); document.write( ": \n" ); document.write( ".25q - .10d = 11 - 5 \n" ); document.write( "; \n" ); document.write( ".15q = 6 \n" ); document.write( "q = \n" ); document.write( "q = 40 quarters \n" ); document.write( "then \n" ); document.write( "50 - 40 = 10 dimes \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution in the total value equation \n" ); document.write( ".25(40) + .10(10) = \n" ); document.write( "10 + 1 = 11 \n" ); document.write( " \n" ); document.write( " |