document.write( "Question 232531: what is the odds in favor of not getting an ace in a standard 52-card deck? \n" ); document.write( "
Algebra.Com's Answer #171813 by stanbon(75887)\"\" \"About 
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what is the odds in favor of not getting an ace in a standard 52-card deck?
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\n" ); document.write( "odds in favor of = P(not getting ace)/P(getting ace)
\n" ); document.write( "= (48/52)/(4/52) = 48/4 = 12/1
\n" ); document.write( "Odds in favor of not getting an ace are 12:1
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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