document.write( "Question 232501: I have got a question could someone explain to me how to convert this into polar coordinates;
\n" ); document.write( "x^2 + y^2 = 4x
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Algebra.Com's Answer #171801 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
x^2+y^2=r^2 \r
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\n" ); document.write( "\n" ); document.write( "x=r*cos(theta)
\n" ); document.write( "y=r*sin(theta)\r
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\n" ); document.write( "\n" ); document.write( "Substitute these into x^2 + y^2 = 4x
\n" ); document.write( "r^2=r*cos(theta)\r
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\n" ); document.write( "\n" ); document.write( "Set equal to zero,
\n" ); document.write( "r^2 -r*cos(theta)=0\r
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\n" ); document.write( "\n" ); document.write( "Factor out the r:
\n" ); document.write( "r(r-cos(theta)) =0 There are TWO solutions.\r
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\n" ); document.write( "\n" ); document.write( "FIRST SOLUTION:
\n" ); document.write( "r=0 which is just a point (0,0)\r
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\n" ); document.write( "\n" ); document.write( "SECOND SOLUTION:
\n" ); document.write( "r-cos(theta) =0\r
\n" ); document.write( "\n" ); document.write( "r=cos(theta)\r
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\n" ); document.write( "\n" ); document.write( "Since the second solution includes the point (0,0), this is automatically included in second solution. The final answer is r=cos(theta).\r
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\n" ); document.write( "\n" ); document.write( "Dr. Robert J. Rapalje
\n" ); document.write( "Seminole State College of Florida\r
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