document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=232478>Question 232478</A>: <I><SPAN STYLE=\"word-break: break-all;\"> howto find the area of the 45-45-90 triangle with a hypotenuse of 24? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #171790 by </B><A HREF=/tutors/aboutme.mpl?userid=rfer><B>rfer(16322)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=171790\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A=.5Lh<BR>\n" );
document.write( "---------------<BR>\n" );
document.write( "a^2+b^2=c^2<BR>\n" );
document.write( "a^2+b^2=24^2<BR>\n" );
document.write( "a^2+b^2=576<BR>\n" );
document.write( "---------------<BR>\n" );
document.write( "legs are equal so divide 576 by 2 then take the sq rt<BR>\n" );
document.write( "576/2=288<BR>\n" );
document.write( "sq rt of 288=16.97<BR>\n" );
document.write( "-------------------<BR>\n" );
document.write( "A=.5Lh<BR>\n" );
document.write( "A=.5*16.97*16.97<BR>\n" );
document.write( "A=144 sq units<BR>\n" );
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