document.write( "Question 232437: big bertha a canon used in could fire shots incredibley long distances. The path of a shell could be modeled by y=-0.0196x(squared) plus 1.137x where x was the horizontal distance traveled(in miles) and why was the height(in miles).How far could Big Bertha fire a shell? what was the shells maximum height?
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #171775 by Stitch(470)\"\" \"About 
You can put this solution on YOUR website!
Given: \"Y+=+%28-.00196%2AX%5E2+%2B+1.137%2AX%29\"
\n" ); document.write( "Y is the height in miles. When Y = 0, the shell is on the ground.
\n" ); document.write( "Solve for Y = 0 and that will give you the distance of the shot.\r
\n" ); document.write( "\n" ); document.write( "\"+0+=+%28-.00196%2AX%5E2+%2B+1.137%2AX%29\"
\n" ); document.write( "Subtract .00196*X^2 from both sides
\n" ); document.write( "\"+.00196%2AX%5E2+=+1.137%2AX\"
\n" ); document.write( "Divide both sides by X
\n" ); document.write( "\"+.00196%2AX+=+1.137\"
\n" ); document.write( "Divide both sides by .00196
\n" ); document.write( "\"X+=+580+miles\"
\n" ); document.write( "So the shell traveled 580 miles\r
\n" ); document.write( "\n" ); document.write( "To find the max height of the shell, you need to see where the slope of the line equals 0.
\n" ); document.write( "The derivative of the lines equation will give you the slope of the line.\r
\n" ); document.write( "\n" ); document.write( "The equation for the line:\"Y+=+%28-.00196%2AX%5E2+%2B+1.137%2AX%29\"
\n" ); document.write( "Now take the derivative
\n" ); document.write( "\"Y%5E1+=+%282%2A-.00196%2AX+%2B+1.137%29\"
\n" ); document.write( "Set the equation equal to 0 to find the max height.
\n" ); document.write( "\"0+=+%28-.00392%2AX+%2B+1.137%29\"
\n" ); document.write( "Subtract -.00392 from both sides
\n" ); document.write( "\".00392%2AX+=+1.137%29\"
\n" ); document.write( "Divide both sides by .00392
\n" ); document.write( "\"X+=+290+miles\"
\n" ); document.write( "Now we know that the maximum height occurs when X = 290 miles.
\n" ); document.write( "Plug X 290 into the original equation
\n" ); document.write( "\"Y+=+-.00196%2AX%5E2+%2B+1.137%2AX\"
\n" ); document.write( "\"Y+=+-.00196%2A290%5E2+%2B+1.137%2A290\"
\n" ); document.write( "\"Y+=+-164.826+%2B+329.73\"
\n" ); document.write( "\"Y+=+164.90+miles\"
\n" ); document.write( "
\n" );