document.write( "Question 232410: Three motorists A, B and C often travel on a certain highway, and each motorist always travels at a constant speed. A is the fastest of the three and C the slowest. \r
\n" ); document.write( "\n" ); document.write( "One day, when the three travel in the same direction, B overtakes C, five minutes later, A overtakes C and in another 3 minutes, A overtakes B. On another occasion when they again travel in the same direction, A overtakes B first, then, nine minutes later, A overtakes C. When will B overtake C?
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Algebra.Com's Answer #171765 by josmiceli(19441)\"\" \"About 
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I tried to extract the information that
\n" ); document.write( "would lead to a solution.
\n" ); document.write( "(a) In both trips, B is the only one that starts and finishes
\n" ); document.write( "(b) Nothing is known about speeds or distances, only times
\n" ); document.write( "(c) For the 1st trip, C travels for 5 min, then A travels for 3 min
\n" ); document.write( "(d) For the 2nd trip, A travels for 9 min, then C travels for ? min
\n" ); document.write( "--------------------------------------------------------------------
\n" ); document.write( "I set up this ratio:
\n" ); document.write( "(A's time on 1st trip) / (time for 1st trip which is B's time) =
\n" ); document.write( "(A's time on 2nd trip) / (time for 2nd trip which is B's time)
\n" ); document.write( "And I could have used this ratio, too:
\n" ); document.write( "(C's time on 1st trip) / (time for 1st trip which is B's time) =
\n" ); document.write( "(C's time on 2nd trip) / (time for 2nd trip which is B's time)
\n" ); document.write( "-------------------------------------------------------
\n" ); document.write( "Let \"C\" = C's time for last part of 2nd trip (B overtakes C)
\n" ); document.write( "Using the 1st ratio:
\n" ); document.write( "\"3%2F8+=+9%2F%289+%2B+C%29\"
\n" ); document.write( "\"3%2A%289+%2B+C%29+=+72\"
\n" ); document.write( "\"27+%2B+3C+=+72\"
\n" ); document.write( "\"3C+=+45\"
\n" ); document.write( "\"C+=+15\" min
\n" ); document.write( "---------------------
\n" ); document.write( "Using the 2nd ratio:
\n" ); document.write( "\"5%2F8+=+C%2F%289+%2B+C%29\"
\n" ); document.write( "\"8C+=+5%2A%289%2BC%29\"
\n" ); document.write( "\"8C+=+45+%2B+5C\"
\n" ); document.write( "\"3C+=+45\"
\n" ); document.write( "\"C+=+15\" min
\n" ); document.write( "B will overtake C in 15 min
\n" ); document.write( "and
\n" ); document.write( "Plugging \"C+=+15\" back into the ratios, I get
\n" ); document.write( "\"3%2F8+=+9%2F24\"
\n" ); document.write( "and
\n" ); document.write( "\"5%2F8+=+15%2F24\"
\n" ); document.write( "Both are true\r
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