document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=232388>Question 232388</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A triangle's sides have lengths 1/(x+2), 1/(x+1) and 1/x what are the possible values of x?\r<BR>\n" );
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document.write( "a) 0 < x < square root 2  b) x > 0  c) x > 1   d) x< 1  e) x > square root 2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #171736 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=171736\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x>0 will do, since the sides of the triangle cannot be negative.  In addition, the values of x must NEVER cause a denominator to be zero, which means that ALSO, x cannot be 0, -1, or -2.  However, if you select x>0, you have eliminated these problems as well.\r<BR>\n" );
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document.write( "Dr. Robert J. Rapalje, Retired<BR>\n" );
document.write( "Seminole State College of Florida\r<BR>\n" );
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