document.write( "Question 232387: If Leah is 6 years older than Sue and John is 5 years older than Leah, the total of their ages is 41. How old is Sue? please help! \n" ); document.write( "
Algebra.Com's Answer #171734 by ptaylor(2198) You can put this solution on YOUR website! Let x=Sue's age \n" ); document.write( "Then x+6=Leah's age \n" ); document.write( "And (x+6)+5=x+6+5=x+11=John's age \n" ); document.write( "And we are told that the above ages add up to 41, so: \n" ); document.write( "x+x+6+x+11=41 collecting like terms we get: \n" ); document.write( "3x+17=41 subtract 17 from each side \n" ); document.write( "3x+17-17=41-17 collect like terms again \n" ); document.write( "3x=24 divide each side by 3 \n" ); document.write( "x=8------------------Sue's age \n" ); document.write( "x+6=8+6=14-------------Leah's age \n" ); document.write( "x+11=8+11=19--------------John's age\r \n" ); document.write( "\n" ); document.write( "CK \n" ); document.write( "Leah is 6 years older than Sue 8+6=14 OK \n" ); document.write( "John is 5 years older than Leah 14+5=19 OK \n" ); document.write( "Their ages add up to 41; 8+14+19=41 OK\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor \n" ); document.write( " |