document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=232356>Question 232356</A>: <I><SPAN STYLE=\"word-break: break-all;\"> When Mendel conducted his famous genetics experiment with peas, one sample of offspring consisted of 428 green peas and 152 yellow peas find a 95% confidence interval estimate of the percentage of yellow peas </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #171729 by </B><A HREF=/tutors/aboutme.mpl?userid=vincysam><B>vincysam(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=vincysam><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=171729\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Total Number of Peas (n) = 428+152= 580<BR>\n" );
document.write( "Sample proportion of yellow peas (p) = 152/580 = 0.262<BR>\n" );
document.write( "And q = 1-p = 1-0.262 = 0.738\r<BR>\n" );
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document.write( "Here the sample size (580) is greater than 30, using Central limit theorem we can expect it approximately follows normal distribution.\r<BR>\n" );
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document.write( "95% confidence interval estimate of the percentage of yellow peas = p (plus or minus)zat0.95*sqrt(p*q/n)<BR>\n" );
document.write( "Standard Normal score at 5% level of significance  = 1.96 <BR>\n" );
document.write( "95% confidence interval estimate of the percentage of yellow peas is<BR>\n" );
document.write( "=  0.262(plus or minus)1.96*sqrt(0.262*0.738/580)<BR>\n" );
document.write( "= 0.262(plus or minus)0.0183<BR>\n" );
document.write( "= (0.2437, 0.2803)<BR>\n" );
document.write( " </SPAN>\n" );
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