document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=232339>Question 232339</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two cars are 900 miles apart both cars start at the same time and travel toward one another they meet 8 hours later if the speed of one car is 30 miles per hour faster than the other what is the exact speed of the faster car. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #171727 by </B><A HREF=/tutors/aboutme.mpl?userid=half-life><B>half-life(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=half-life><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=171727\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x equal the speed of the slower car in mph.  This means the speed of the faster car is x +30.\r<BR>\n" );
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document.write( "If both cars cars are moving towards each other we can add the two speeds together and treat the problem as one moving car.\r<BR>\n" );
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document.write( "x +x +30 = 2x +30\r<BR>\n" );
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document.write( "distance = (speed)(time)\r<BR>\n" );
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document.write( "900 = (2x +30)(8)\r<BR>\n" );
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document.write( "900 = 16x +240\r<BR>\n" );
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document.write( "16x = 660\r<BR>\n" );
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document.write( "x = 41.25mph\r<BR>\n" );
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document.write( "add 30 to find the speed of the faster car which is 71.25mph </SPAN>\n" );
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