document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=232305>Question 232305</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1.state the general solution to the equation sec2x=-3\r<BR>\n" );
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document.write( "2. use an algebraic approach to solve the equation cos3x=-1/2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #171715 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=171715\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> state the general solution to the equation sec2x=-3<BR>\n" );
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document.write( "If sec(2x) = -3<BR>\n" );
document.write( "then cos(2x) = -1/3<BR>\n" );
document.write( "Find the arccos(-1/3) = 109.47 + 720n degrees OR -109.47 + 720n degrees<BR>\n" );
document.write( "2x = 109+720n OR 2x = -109.47+720n <BR>\n" );
document.write( "x = 54.5+360n degrees OR x = -54.4+360n degrees<BR>\n" );
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document.write( "2. use an algebraic approach to solve the equation cos3x=-1/2<BR>\n" );
document.write( "3x = arccos(-1/2)<BR>\n" );
document.write( "3x = 120 degrees OR 240 degrees<BR>\n" );
document.write( "x = 40 degrees OR 80 degrees<BR>\n" );
document.write( "======================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
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