document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=232286>Question 232286</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a chemist needs a 30% iron alloy. How many grams of a 70% iron alloy must be mixed with 16 grams of a 20% iron alloy to obtain the required 30% alloy </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #171698 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=171698\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a chemist needs a 30% iron alloy. How many grams of a 70% iron alloy must be mixed with 16 grams of a 20% iron alloy to obtain the required 30% alloy<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "iron + iron = iron<BR>\n" );
document.write( "0.70x + 0.20*16 = 0.30(x+16)<BR>\n" );
document.write( "Multiply thru by 100 to get:<BR>\n" );
document.write( "70x + 20*16 = 30x + 30*16<BR>\n" );
document.write( "40x = 10*16<BR>\n" );
document.write( "x = 4 grams (amount of 70% alloy needed in the mix)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );