document.write( "Question 232224: I have two gallons of grape drink that is one-third water, and I mix it with three gallons of lemonade that is three-fourths water. After mixing, I spill one gallon of the mixture. How much water is there in the remaining four gallons of the mixture? \n" ); document.write( "
Algebra.Com's Answer #171684 by stanbon(75887)\"\" \"About 
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I have two gallons of grape drink that is one-third water, and I mix it with three gallons of lemonade that is three-fourths water. After mixing, I spill one gallon of the mixture. How much water is there in the remaining four gallons of the mixture?
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\n" ); document.write( "Equation:
\n" ); document.write( "water + water = water
\n" ); document.write( "(1/3)2 + (3/4)3 = r(5) where r is the fraction of water in the mixture
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\n" ); document.write( "(2/3) + (9/4) = 5r
\n" ); document.write( "35/12 = 5r
\n" ); document.write( "r = 7/12
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\n" ); document.write( "7/12 of the 5 gallon mixture is water
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\n" ); document.write( "You spill 1 gallon of the mixture; you are left with
\n" ); document.write( "(7/12)4 = (7/3)gallon of water in the 4 gallon mixture.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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