document.write( "Question 232225: find the vertex and graph of y= -x2 + 6x - 5.5 \n" ); document.write( "

Algebra.Com's Answer #171675 by stanbon(75887) $\"\"$ $\"About$

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find the vertex and graph of y= -x^2 + 6x - 5.5
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\n" ); document.write( "You have a quadratic with a=-1, b = 6, c = -5.5
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\n" ); document.write( "Vertex occurs when x = -b/2a = -6/(-2) = 3
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\n" ); document.write( "The corresponding y-value is:
\n" ); document.write( "f(3) = -(3)^2 + 6*3 - 5.5 = -14.5 +18 = 3.5
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\n" ); document.write( "So, vertex at (3,3.5)
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\n" ); document.write( "y-intercept at f(0) = -5.5
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\n" ); document.write( "Parabola opens downward because a < 0.
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\n" ); document.write( " $\"graph%28400%2C300%2C-10%2C10%2C-20%2C10%2C-x%5E2%2B6x-5.5%29\"$
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "

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